From bfd412e726f701e576713590e41da508dee829b1 Mon Sep 17 00:00:00 2001
From: =?UTF-8?q?=E7=94=B2=E8=BE=B0=E7=94=9F=E4=BA=A7?= <jiachenlong@local>
Date: Sun, 12 Apr 2026 00:40:16 +0800
Subject: [PATCH] =?UTF-8?q?=E4=BF=AE=E5=A4=8D9=E4=BD=8D=E6=95=B0=E5=AD=97?=
 =?UTF-8?q?=E8=A2=AB=E9=94=99=E8=AF=AF=E7=9F=AB=E6=AD=A3=E9=97=AE=E9=A2=98?=
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---
 backend/app/routers/information.py | 12 ++++++------
 1 file changed, 6 insertions(+), 6 deletions(-)

diff --git a/backend/app/routers/information.py b/backend/app/routers/information.py
index 82db926..1484998 100644
--- a/backend/app/routers/information.py
+++ b/backend/app/routers/information.py
@@ -1279,15 +1279,15 @@ async def batch_parse_deals(text: str = Body(..., embed=True)):
                 data = json.loads(content.strip())
                 # 对AI返回的数据进行冠字号矫正
                 def normalize_serial_ai(num_str):
-                    """矫正冠字号：确保是J0+9位数字"""
+                    """矫正冠字号：确保是J0+9位数字，只对位数不对的进行矫正"""
                     if not num_str.startswith('J0'):
                         return None
                     num = num_str[2:]  # 去掉J0
                     diff = 9 - len(num)
+                    # 位数正好9位，不需要矫正
                     if diff == 0:
                         return num_str
                     elif diff == -1:
-                        # 多1位，去掉倒数第4位
                         if len(num) >= 4:
                             result = num[:5] + num[-4:]
                             if len(result) == 9:
@@ -1379,22 +1379,22 @@ def parse_deals_locally(text: str, default_packaging: str = '', default_date: st
         if not serial_match:
             continue
         
-        # 冠字号矫正函数
+        # 冠字号矫正函数 - 只对位数不对的进行矫正
         def normalize_serial(num_str):
             """矫正冠字号：确保是J0+9位数字"""
             num = num_str
             diff = 9 - len(num)
+            
+            # 位数正好9位，不需要矫正
             if diff == 0:
                 return 'J0' + num
+            # 位数不对才需要矫正
             elif diff == -1:
                 # 多1位（10位数字）→ 去掉倒数第4位
-                # 例如: 298810101 → 去掉第4位(0) → 2988101 + 01 = 298810101 (9位)
                 if len(num) >= 4:
-                    # 取前5位 + 最后4位
                     result = num[:5] + num[-4:]
                     if len(result) == 9:
                         return 'J0' + result
-                    # 如果还是不对，尝试去掉第5位
                     result2 = num[:4] + num[-5:]
                     if len(result2) == 9:
                         return 'J0' + result2